FYBCOM Maths Sem 2 MCQ Questions with Answers: Mumbai University 2021

FYBCOM Maths Sem 2 MCQ Questions with Answers

F.Y.B.Com Sem-II MCQ Mathematical & Statistical Techniques for  April,2021

QuestionAnswer1Answer2Answer3Answer4Correct Answer
If y = ex + 5x – 10 then dy / dx is —–exex +  555xAnswer2
If y =   log 6  then dy/dx islog 661/60Answer4
If y= (5x+1)(5x-1)  then dy/dx is2x50 x5 x25 xAnswer2
If elasticity of demand is 1 ,  then demand is said to be —–unelasticinelasticperfectly
elastic
directly
proportional to
Answer4
If D is the number of units demanded and the price is  p = 50 + 2D, then the average revenue when  D = 10 is Rs.—–357010010Answer2
If y = u + v , then dy/dx isv du/dx + u dv/dx –kdu/dx +dv/dxk. du/dx.
dv/dx
v du/dx + u dv/dx
+k
Answer2
If y = u v  , then dy/dx is[v du/dx + u dv/dx ](v du/dx)- (u
dv/dx )
01Answer1
If y = 2x2 + 3x  + 20  then dy/dx is4x4x + 3203xAnswer2
If  D is the number of units  demanded and the price is  p = 30 + D , then the revenue when D =2 is Rs.—–64706054Answer1
A break- even point is the stage when—–everything breaks downthe market crashesthe demand
and supply balance
Interest is nullAnswer3
If  C =  x2 + 10 x + 10 where x is number of units produced, find marginal cost at x = 21014220Answer2
The demand function is D=1+4p-p3.  Then the rateof change of Demand w.r.t. price at p=1, is0-1110Answer3
The cost of manufacturing x toys is C=x2  -5x+7. Then the marginal cost of manufacturing 10 toys is Rs.—5715105Answer2
The demand function of a commodity is p=3+5D-D2, where p is the price. Then the rate at which its price is changing when demand is 5 is—-105-10-5Answer4
The point of maxima for the  function  f(x) =3+4x-x2  is x = —–2134Answer1
If the Profit Function in lakhs, for selling x tons of good is p(x)=  – x2  +  8x+28, then at what value of x, we have  max profit in lakhs.2431Answer2
For the demand function D =2  –  3p  + p2    , the demand when the price p= 5, is ——10151220Answer3
The total cost function of producing certain article is C= x2  – 5x +100. So the average cost of producing 10 such items is—15102025Answer1
The demand for a certain goods in the market is D = 10 – p2 , where p is its price . So its total revenue when the price is Rs. 3 per unit is310100Answer1
If elasticity of demand is zero ,   then demand is said to be —–perfectly elasticinelasticelasticdirectly proportional to
price
Answer1
If y= 10 x2 + 7x + 1000  then dy/dx is20x20 x + 710007Answer2
If y= 63     then dy/dx is—2160log 66Answer2
If y=  5x + 15 x + log 5   then dy/dx is—–15x + log 5log 55x log 5  + 151Answer3
If y= x3 + 4x then dy/dx is—–3x + 43x 2 + 443x2Answer2
If y= 5 log x   + 15 x then dy/dx is——1/x15/x  + 155xAnswer3
If y =  5 x8 + log x then dy/dx is —-log x40 x40x7 +  1/x40 x7Answer3
If  0 <  ղ( elasticity of demand) < 1 , the demand is said to be —–inelasticperfectly elasticdirectly proportional
to price
elasticAnswer1
If    ղ( elasticity of demand)  > 1 , the demand is
said to be —–
inelasticperfectly elasticdirectly proportional
to price
elasticAnswer4
The cost function of a commodity is given by  C =   10x2   –  400 x  + 100 , x being the quantity produced. Find the quantity x for which the cost is minimum.3051020Answer4
The total Revenue function of a commodity is given by R =   -5x2  + 40 x  + 300 , x being the quantity demanded . Find the quantity x for which the revenue  is maximum.5431Answer2
If y = 15 x2 ,  then d2 y / d2 x is ——153030 x0Answer2
If y =  e x + 10x2  ,  then d2y / d2x is ——ex10 x20 xex + 20Answer4
If the demand function is  D = 25 – 3p ,where D is demand and p is price, find the elasticity of demand at p = 50.501.5022.50Answer2
If the demand function is  D = 10 – 2p ,where D is demand and p is price, find the elasticity of demand at p = 22/31/311/4Answer1
If the Revenue function is given by R = D2 – D + 10 . Find the marginal revenue  if the number of units demanded (D) = 1.7614Answer3
If the Revenue function is given by R =  10 D2 + 10 D  – 2. Find the  marginal revenue  if the number of units demanded (D) = 2040010410450Answer3
If the demand function is given by p = 20 + 10D. Find the average revenue   if the number of units demanded (D) = 4.6010065250Answer1
If the cost function of manufacturing x items is given by 5x2 +10 x+ 20. Find the average cost if 2  items are made( x = 2)60302040Answer2
A function is given as f(x) = 10 x2 + 5x  – 10 , find its value at x = 1-55010Answer2
A function is given as f(x) =  6x2 – 2x  + 15 , find its value at x = 23053510Answer3
The simple interest  at 20% on Rs. 60,000  for 5
years is Rs.—-
60,0001,20,00050,00065,000Answer1
A bank promises to double the principal invested by their customers in 10 years. What
is the rate of simple interest offered by the
8%10%12%14%Answer2
The   compound   interest   for   3   years   on   Rs. 15,000  at  the  rate  of  8%  per  year,  calculated annually is approx. Rs.—-5,0003,8963,5002,950Answer2
The difference between the compound interest and the simple interest on a principal P, placed at 10% p.a. , compounded annually for 2 years is Rs. 50, then the principal P is Rs. —–3000004000005000600000Answer3
A fixed sum kept on compound interest got Rs. 800  in  the  first  year  and  Rs.  864  in  the  next year.       Find   the   rate   of   interest    ,   when compounded annually.9%7%8%10%Answer3
A  sum  of  Rs. 25000  accumulated to  Rs. 55000 after 12 years. Find the rate of S.I. p.a.30%10%40%50%Answer2
The Compound interest  at 10 % on Rs. 40,000
for 2 years is Rs.—
8,0009,5008,40012,000Answer3
After   how   many   years,   a   sum   of   Rs.   6400 accumulated to  an amount of Rs. 9280 at  9% p.a. rate of simple Interest?12 years13 years5 years10 yearsAnswer3
Ajay opened a recurring deposit account of Rs. 2,000 at the end of each year for 2 years. What is  the  accumulated  amount  if  the  interest  is compounded at 10% p.a.?Rs. 3,800Rs.2,500Rs. 4,200Rs.3,545Answer3
The    approximately    present    value    of    an immediate  annuity  of Rs. 500/-  per year  for  4 years with interest compounded at 11 % p.a.Rs.2,500Rs.1,551Rs.2,840Rs.3,400Answer2
Priya took some money from his friend at simple interest of 6 % per annum. She returned her friend Rs.1,180. After how much time did Priya return the money if she borrowed Rs. 1,000?3 years4years2 years6yearsAnswer1
Manisha took a loan from a bank for 4 years at 12 % p.a. rate of simple interest. She paid Rs.1,440 as interest on a loan taken by her.
What was the amount she took as loan?
Rs.3,000Rs.5,500Rs.6,400Rs.3,880Answer1
Suresh  invested Rs. 500 in SBI for 2 years. He also invested Rs. 300 in ICICI for 4 years. At the end he received Rs. 220 in all from banks as total simple interest. What must have been rate of interest?10%11%12%9%Answer1
An amount of Rs.5,000 was borrowed by Anjali
, at a simple interest of 15 % p.a. . She returned the amount with interest after 4 years. Calculate the  total amount returned by her.
Rs.5,000Rs.6,000Rs.8,000Rs.8,500Answer3
The simple interest  at 14 % on Rs. 200 for 3 years is Rs—–588445100Answer2
The simple interest at 9 %, for a fixed deposit at the  end  of  6  years  was  Rs.  2,700,  then  the principal  of the fixed  deposit was Rs.—-5,0005,5004,8003,400Answer1
At what rate a principal of Rs. 5,000 be put for 4  years,  so  as  to  get  Rs.2,400   as  interest on Maturity ?6%12%10%8%Answer2
When  the  interest  is  compounded  annually  , the   maturity   amounts   of   a   fixed   deposit obtained  at   the  end  of  one  year  using  the compound   interest   as   well    as   the   simple interest are identical.TRUEFALSEPartially trueDepends on the principalAnswer1
I  keep  Rs.  100  for simple interest in a  bank at 10%   for   2   years.   My friend keeps   Rs.   100 for compound interest at 10% for 2 years. If his interest is compounded annually,  what is the difference in our interests on maturity?Rs.100Rs.1Rs.10Rs.1000Answer2
A  person  borrowed  Rs  15,000  at  12%  interest
p.a.  If  he  is  supposed  to  return  the  money within 1 year, then his EMI using Flat  Rate of Interest will be  Rs.—
Rs.2,500Rs.1,800Rs.2,000Rs.1,400Answer4
Ruby borrowed Rs. 60,000 at  8 % interest p.a. If she is supposed to return the money within 2 years, then her  EMI using Flat Rate of Interest
will be  Rs.—
3,6002,0002,900900Answer3
The future value of Rs. 25,000 kept in a bank, after 1 year at a 15% rate of compound interest p.a. is Rs.—-28,75030,00032,40025,300Answer1
The future value of Rs.45,000 kept in a fixed deposit account, after 2 years at  12 % rate of compound interest p.a. is Rs.—-40,00056,44842,00035,000Answer2
The difference between the compound interest and the simple interest on a principal P, placed at 10% p.a. , compounded annually for 4 years is Rs. 1282, then the principal P is Rs. —-20,00010,00015,00025,000Answer1
A sum of Rs. 12,000 accumulated to Rs. 17,280 at 20%p.a.compound interest. Find the period.1year3year2year4yearAnswer3
A sum of Rs.24,000 accumulated to Rs. 34,560 after a certain period , at  20 % p.a. rate of compound interest p.a.. Find the period1 year4 year3 year2 yearAnswer4
Find the approx present value of Rs.15,000 payable 3 years hence ,if the interest is compounded annually at 9 % p.a.Rs.15,700Rs.16,450Rs.11,583Rs.16,000Answer3
Preeti kept a certain amount in a fixed deposit in a bank which offered 10% rate of interest , compounded annually. At the time of maturity , after 4 years she received Rs. 73,205. Find the Principal amountRs.50,000Rs.80,000Rs.75,000Rs.85,000Answer1
Ramesh deposited Rs. 8000 at the end of every year in a bank for 4 years. How much amount of annuties he received at the end if the rate of interest being 8 % p.a.Rs. 32,000Rs.30000Rs.25,000Rs.36,050Answer4
Radhika opened a recurring deposit in a bank for 6 years with payment of Rs. 5000. Find the total amount of annuties she will receive at the end of period with 9 % p.a.Rs.37,617Rs.30,000Rs.25,000Rs.27,000Answer1
Find the present value of an annuity of Rs. 2,000,paid at the end of each year for 4 years , at 11 %  compounded annually.Rs.8,000Rs.6,205Rs.8,200Rs.9,000Answer2
_is an interest earning fund , in which equal deposits are made at equal interval of time .Mutual fundSinking FundEMILoanAnswer2
Find the approx. present value of an annuity of Rs. 2,000 paid at the end of each year for 3 years , at 6 %  compounded annuallyRs.8,760Rs.5,346Rs.6,700Rs.7,500Answer2
Amita deposited Rs. 5000 at the end of every year in a R. D. account  for 3 years. How much amount of annuties she received at the end if the rate of interest being 12 % p.a.Rs.10,300Rs.14,000Rs.12,200Rs.16,872Answer4
Puja took a loan of Rs.40,000  to be repaid in 2 year at  6 % p.a. . Find the approx.  EMI by Flat
interest rate method.
Rs.3,500Rs.4,400Rs.2,500Rs.1,867Answer4
Mansi  takes a loan of Rs. 2,40,000 from a bank for a period of 10 months. Compute  the EMI at 10 % p.a.by Flat interest rate method.Rs. 18,200Rs.30,000Rs.26,000Rs.25,500Answer3
Rajesh   takes a loan of Rs.10,000 from a financial institution for a period of  4 months. Compute  the EMI at 12 % p.a.by Flat interest
rate method.
Rs.2,600Rs.5,000Rs.3,500Rs.7,200Answer1
For EMI , rate of interest should be —-per annumper quarterper monthper half yearAnswer3
The sum invested /borrowed is called the ——Interestaccumulated
amount
EMIprincipalAnswer4
A series of equal payments made at equal
interval of time is called the —–
PrincipalAmountAnnuityInterestAnswer3
If there exit a relation between a pair of
variables ( x and y) then it is called
correlationA.M.G.M.MedianAnswer1
A statistical data consisting of two variables is
called a
multivariatebivariateunivariatepolynomialAnswer2
If both variables increase or decrease together
then there is           correlation
negativenopositiveperfect negativeAnswer3
The correlation coefficient lies between± 1± 2± 30 & 1Answer1
A pictorial representation of the correlation is
called
scatter diagrambar diagramhistogrampie chartAnswer1
For Perfectly positive correlation r =-1-21-3Answer3
If the value of Pearson’s coefficient of correlation is – 0.93, it can be concluded that there isHigh degree of Positive correlationPerfect negative
correlation
No correlationHigh degree of negative correlationAnswer4
For positive correlation if x  increases then y increases or if x decreases then —–y increasesy decreasesno change in yy increases and decreases bothAnswer2
If changes in x does not affect the changes in y then there is          correlationpositivenegativenoperfect positiveAnswer3
The relationship between number of strikes of employees of a company and its production  is a example of ——
correlation
positivenegativeperfect positivenoAnswer2
The relationship between height and weight of a student is a example of          correlationnegativeperfect positivenopositiveAnswer4
The relationship between I. Q. of a student and price of petrol  is a example of          correlationpositiveNonegativePerfect positiveAnswer2
If the value of Pearson’s coefficient of
correlation is 1 , it can be concluded that there
is      correlation
Imperfect negativePerfect negativeperfect positiveimperfect positiveAnswer3
If the value of Pearson’s coefficient of
correlation is 0 , it can be concluded that there is —correlation
negativepositivenoperfect positiveAnswer3
The coefficient of rank correlation( R ) between marks given by judge A and judge B to a series of one act play in a drama competition is 0.75.
If  ∑ d2 = 30 then number of  the play group(n) is—-
9111213Answer1
If n= 8 and ∑ d2  = 30  then  Spearman’s rank
coefficient of  correlation( R ) is……
0.8510.642Answer3
If n= 7 ,  ∑ d2   = 45 and ∑ c.f. = 1  then Spearman’s rank coefficient of  correlation( R ) is……0.40.180.50.8Answer2
If n = 4 ,  ∑xy = 88 ,  ∑x = 16 ,  ∑y = 20,  ∑x2 = 80
and  ∑ y2  = 116 then Karl Pearson’s coeff. of
0.410.20.5Answer4
If a rank is repeated twice then value of
correction factor (c.f.) is —–
12.000.51.5Answer3
For the data x : 12 , 15 , 11 , 10   ;  y:  25,30,28,29 . The rank coeff. of correlation is —-
0.20.30.40.5Answer1
If two variables of x & y are highly correlated then y can be estimated for a given value of x using regression equation ofy on yy on xx on xx on yAnswer2
x can be estimated for a given value of y using regression equation of                 If the two variables of x & y are highly correlated.x on xy on yx on yy on xAnswer3
If the two regression coefficients are positive then the value of the correlation coefficient must bepositivenegativezero-1Answer1
The correlation coefficient is always
If the two regression coefficients are negative.
10positivenegativeAnswer4
The Pearson’s correlation  is mean of both the regression coefficient.ArithmeticGeometricHarmoniccubeAnswer2
The regression equation is inter-relation between variables.5421Answer3
If one of the regression coefficient is negative then the another regression coefficient is
.
negativepositive23Answer1
If one of the regression coefficient is  > 1 then the another regression coefficient has to be> 1< 11-1Answer2
If byx = 1.5 & bxy = 0.5 then r =0.5660.6660.7660.866Answer4
If the two regression lines are perpendicular with each other, then the value of correlation coefficient is5403Answer3
If the regression equation of x on y is x + 2y = 40, the estimated value of x when y = 10 is5101520Answer4
The estimated value of y when x = 9 is if the regression equation of y on x is 4x + 3y =
51.
5432Answer1
The value of the Correlation coefficient is      if the regression coefficients are 0.4 and 0.90.50.60.70.8Answer2
The regression equations are given by x + 3y = 88   & 2x + y = 71 then mean values of x & y are                respectively.20 & 2223 & 2625 & 2124 & 27Answer3
The regression equation of y on x is 100y-45x- 1400=0 & that of x on y is 4y-5x+200=0 then r =0.60.70.80.9Answer1
bxy = 1/3 and mean values of x & y are 15 & 20 respectively then regression equation of x on y
is
3x – y = 243x – y = 253x – y = 263x – y = 27Answer2
byx = -4/5 and mean values of x & y are 20 & 25 respectively then regression equation of y on x is4x + 5y = 2024x + 5y = 2034x + 5y = 2044x + 5y = 205Answer4
If r = 0.4 and standard deviation of x & y are 15
& 9 respectively then regression coefficient of y on x is
0.190.220.240.26Answer3
The Regression coefficient of x on y is    If the standard deviation of x & y are 7 & 4 respectively  and r = – 0.8-0.9-1.4-1.6-1.9Answer2
If r = 1/3 & bxy = 2/5 then byx =5/16.5/17.5/18.5/19.Answer3
An orderly set of data arranged in accordance with their time of occurrence is called seriesArithmeticGeometricHarmonicTimeAnswer4
An increase in the number of patients in the hospital due to heatstroke is
variation
RegularIrregularSeasonalNon-SeasonalAnswer3
In time series seasonal variations can occur within a period of   yearFourThreeOneNineAnswer3
The general tendency of the time series data is represented using the following componentTrendrandomconstantvariableAnswer1
In a straight-line equation Y = a + bX; a isX-interceptY-interceptSlopeVariableAnswer2
In a straight-line equation Y = a + bX; b isSlopeVariableX-interceptY-interceptAnswer1
Moving average method is used for measurement of trend when it isvariableconstantnon-linearlinearAnswer4
The most commonly used mathematical method for measuring the trend is by   methodquarterlysemi-annualleast squareVariableAnswer3
Damages due to floods, earthquakes, strikes, fires and political disturbances are variationRegularIrregularSeasonalCyclicalAnswer2
The Additive time series model can be
expressed as
O = T + S + C + IO = T x S x C x IO = T x S x CO = T x SAnswer1
The multiplicative time series model can be expressed asO = T + S + C + IO = T x S x C x IO = T + S + CO = T + SAnswer2
Index numbers are expressed in ratioSquarescubesPercentagePermutationAnswer3
Index for base period is always taken as100200300400Answer1
In chain base method, the base period isFourThreeTwoNot FixedAnswer4
Price relatives are a percentage ratio of current year price andBase year quantityPrevious year
quantity
Base year
price
Current year
quantity
Answer3
Another name of consumer’s price index number isWholesale indexCost of living
index
Sensitive
index
Composite indexAnswer2
Cost of living index numbers are obtained by formulaLaspeyre’sPaasche’sFisherMarshall
Edgeworth
Answer1
When the current price is divided by the price of the preceding year, we get        relativenon-linkCompoundComplexlinkAnswer4
The method of link relatives is used to calculate indexPaasche’sFisherChain BaseLaspeyre’sAnswer3
A number that measures a relative change in a single variable with respect to a base is NumberGood IndexGreat IndexSimple IndexQuantity IndexAnswer3
The Trend value data for 3 consecutive years is 58, 62 & 78  then 3 yearly moving average is55667788Answer2
The Trend value data for 5 consecutive years is 73, 82, 95, 102 & 103  then 5 yearly moving average is89909192Answer3
To obtain 5 yearly moving average for a year the corresponding 5 yearly moving total is to be divided by5432Answer1
The 4 yearly moving average for a year whose corresponding 4 yearly centered total is 496 has to be60616263Answer3
The 3 yearly moving average for a year whose corresponding 3 yearly moving total is 546 has to be182183184185Answer1
The 5 yearly moving average for a year whose corresponding 5 yearly moving total is 265 has to be50515253Answer4
If a = 5 & b = 7 then the Trend line equation is given byy = 7 + 5xy = 5 + 7xx = 5 + 7yx = 7 + 5yAnswer2
If n = 7 then to find trend line equation y = a + bx by least square method x takes the values as,-3,-2,-1,0,1,2,3,,1,2,3,4,5,6,7,,1,3,5,7,9,11,1
3,
,2,4,6,8,10,12,14,Answer1
If n = 6 then to find trend line equation y = a + bx by least square method x takes the values as,1,2,3,4,5,6,,-5,-3,-1,1,3,5,,1,3,5,7,9,11,,2,4,6,8,10,12,Answer2
If ∑y = 240 & n = 12 then in trend line equation y = a + bx we have a =17181920Answer4
If ∑P0 = 80 & ∑P1= 100 then simple index number by aggregative method is115120125130Answer3
If ∑i = 480 & n = 6 then simple index number by average of price relative method is50607080Answer4
If ∑P0w = 303 & ∑P1w = 500 then index number by weighted aggregative method is145.02155.02165.02175.02Answer3
If ∑iw = 4200 &  ∑w = 20 then cost of living index number by family budget method is200210220230Answer2
If ∑p1q0 = 400 & ∑p0q0 = 210 then Laspeyre’s Index number =190.48192.48194.48196.48Answer1
If ∑p1q1 = 1610 & ∑p0q1 = 1090 then Paasche’s Index number =137.71147.71157.71167.71Answer2
If Laspeyre’s  & Paasche’s Index number are 80 & 90 respectively then Fisher’s Index number is64.8574.8584.8594.85Answer3
If Laspeyre’s  & Paasche’s Index number are 64 & 72 respectively then Dorbish-Bowley’s Index number is62646668Answer4
If ∑p1q0 = 400, ∑p0q0 = 210, ∑p1q1 = 490 & ∑p0q1 = 300 then Marshal Edgeworth’s Index number =164.51174.51184.51194.51Answer2
Dorbish-Bowley’s Index number is           of Laspeyre’s  & Paasche’s Index numberHarmonic MeanGeometric MeanDifferenceArithmetic meanAnswer4
The mean of the binomial distribution is given
by
nnpnpqp+qAnswer2
The variance of the binomial distribution is given byp+qnnpnpqAnswer4
The variance of binomial distribution is always mean.thrice tomore thanless thantwice theAnswer3
Each trial in the binomial distribution has
possible outcomes.
1234Answer2
In binomial distribution we always have p + q =1357Answer1
The mean of Poisson’s distribution is always variance.more thanless thantwice theequal toAnswer4
The Poisson distribution has a parameter.3210Answer3
The mean of the Poisson’s distribution is given bymnpqp+qAnswer1
The variance of the Poisson’s distribution is given bypqmp+qnAnswer2
We use Poisson’s distribution when ‘n’ is large & probability of success (p) islargenot knownfixedsmallAnswer4
In  Normal distribution, Total area under the normal curve is4321Answer4
We use normal distribution when x issmallcontinousnot knownfixedAnswer2
In  Normal distribution, Shape of normal curve can be related tosquarerectangletrianglebellAnswer4
In case of symmetrical normal distribution we
always have
mean = mode =
median
mean < modemean > modemean < medianAnswer1
The normal distribution has parameters.0123Answer3
In  Normal distribution, the shape of normal curve depends upon  deviationGeometricStandardQuartileQuadraticAnswer2
In  Normal distribution, the normal curve is symmetrical abouty = 2xx = 2yy = meanx = meanAnswer4
In  Normal distribution, area under the normal curve on either side of ordinate is0.50.60.70.8Answer1
In  Normal distribution, the Quartile deviation is  standard deviationmore thanless thanequal tothrice theAnswer2
In  Normal distribution, the Standard deviation is Mean deviationless thanequal tomore thantwice theAnswer3
In a binomial distribution, If mean = 4 and n = 5 then p =0.80.70.60.3Answer1
In a binomial distribution, If n = 8 and mean = 2.4 then q =0.20.40.60.7Answer4
In a binomial distribution, If mean = 3 and p = 0.5 then n =8765Answer3
In a binomial distribution, If n = 6 and q = 0.7 then mean =11.823Answer2
In a binomial distribution, If p = 0.4 and n = 7 then variance =321.681Answer3
In a binomial distribution, If  variance = 0.8 and q = 0.8 then n =1235Answer4
In a binomial distribution, If  mean = 3 and variance = 2.4 then p =0.20.30.40.5Answer1
In a binomial distribution, If variance = 2 and mean = 3 then n =891012Answer2
In a binomial distribution, If n = 5 and p = 0.6 then mode =2436Answer3
In a binomial distribution, If n = 4 and q = 2/3 then P(X=4) =1/21.1/31.1/41.1/81.Answer4
In a Poisson’s distribution, If n = 300 and p = 1% then mean =0369Answer2
In a Poisson’s distribution, If variance = 2 and p = 4% then n =50607080Answer1
In a Poisson’s distribution, If mean = 3.8  then mode =0235Answer3
In a Poisson’s distribution, If mean = 4  then standard deviation =1235Answer2
In a Poisson’s distribution, If P(X=1) = P(X=2) then m =7532Answer4
In a Poisson’s distribution, If standard deviation= 3 and n = 300 then p =            %0234Answer3
In a Poisson’s distribution, If P(X<1) = 0.83 then P(atleast one) =0.170.180.190.21Answer1
In a Poisson’s distribution, If P(X = 0) = 0.14, P(X= 1) = 0.17 & P(X = 2) = 0.23 then P(X < 3) =0.240.320.410.54Answer4
In a Normal distribution, If P(0 < z < 2) = 0.4772 then P(-2 < z < 2) =0.62550.95440.72550.8255Answer2
In a Normal distribution, If P(0 < z < 1) = 0.3413 then P(z > 1) =0.13550.14550.15870.1655Answer3

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