FYBCOM Maths Sem 2 MCQ Questions with Answers: Mumbai University 2021


FYBCOM Maths Sem 2 MCQ Questions with Answers

F.Y.B.Com Sem-II MCQ Mathematical & Statistical Techniques for  April,2021

Question Answer1 Answer2 Answer3 Answer4 Correct Answer
If y = ex + 5x – 10 then dy / dx is —– ex ex +  5 5 5x Answer2
If y =   log 6  then dy/dx is log 6 6 1/6 0 Answer4
If y= (5x+1)(5x-1)  then dy/dx is 2x 50 x 5 x 25 x Answer2
If elasticity of demand is 1 ,  then demand is said to be —– unelastic inelastic perfectly
elastic
directly
proportional to
Answer4
If D is the number of units demanded and the price is  p = 50 + 2D, then the average revenue when  D = 10 is Rs.—– 35 70 100 10 Answer2
If y = u + v , then dy/dx is v du/dx + u dv/dx –k du/dx +dv/dx k. du/dx.
dv/dx
v du/dx + u dv/dx
+k
Answer2
If y = u v  , then dy/dx is [v du/dx + u dv/dx ] (v du/dx)- (u
dv/dx )
0 1 Answer1
If y = 2x2 + 3x  + 20  then dy/dx is 4x 4x + 3 20 3x Answer2
If  D is the number of units  demanded and the price is  p = 30 + D , then the revenue when D =2 is Rs.—– 64 70 60 54 Answer1
A break- even point is the stage when—– everything breaks down the market crashes the demand
and supply balance
Interest is null Answer3
If  C =  x2 + 10 x + 10 where x is number of units produced, find marginal cost at x = 2 10 14 2 20 Answer2
The demand function is D=1+4p-p3.  Then the rateof change of Demand w.r.t. price at p=1, is 0 -1 1 10 Answer3
The cost of manufacturing x toys is C=x2  -5x+7. Then the marginal cost of manufacturing 10 toys is Rs.— 57 15 10 5 Answer2
The demand function of a commodity is p=3+5D-D2, where p is the price. Then the rate at which its price is changing when demand is 5 is—- 10 5 -10 -5 Answer4
The point of maxima for the  function  f(x) =3+4x-x2  is x = —– 2 1 3 4 Answer1
If the Profit Function in lakhs, for selling x tons of good is p(x)=  – x2  +  8x+28, then at what value of x, we have  max profit in lakhs. 2 4 3 1 Answer2
For the demand function D =2  –  3p  + p2    , the demand when the price p= 5, is —— 10 15 12 20 Answer3
The total cost function of producing certain article is C= x2  – 5x +100. So the average cost of producing 10 such items is— 15 10 20 25 Answer1
The demand for a certain goods in the market is D = 10 – p2 , where p is its price . So its total revenue when the price is Rs. 3 per unit is 3 1 0 100 Answer1
If elasticity of demand is zero ,   then demand is said to be —– perfectly elastic inelastic elastic directly proportional to
price
Answer1
If y= 10 x2 + 7x + 1000  then dy/dx is 20x 20 x + 7 1000 7 Answer2
If y= 63     then dy/dx is— 216 0 log 6 6 Answer2
If y=  5x + 15 x + log 5   then dy/dx is—– 15x + log 5 log 5 5x log 5  + 15 1 Answer3
If y= x3 + 4x then dy/dx is—– 3x + 4 3x 2 + 4 4 3x2 Answer2
If y= 5 log x   + 15 x then dy/dx is—— 1/x 1 5/x  + 15 5x Answer3
If y =  5 x8 + log x then dy/dx is —- log x 40 x 40x7 +  1/x 40 x7 Answer3
If  0 <  ղ( elasticity of demand) < 1 , the demand is said to be —– inelastic perfectly elastic directly proportional
to price
elastic Answer1
If    ղ( elasticity of demand)  > 1 , the demand is
said to be —–
inelastic perfectly elastic directly proportional
to price
elastic Answer4
The cost function of a commodity is given by  C =   10x2   –  400 x  + 100 , x being the quantity produced. Find the quantity x for which the cost is minimum. 30 5 10 20 Answer4
The total Revenue function of a commodity is given by R =   -5x2  + 40 x  + 300 , x being the quantity demanded . Find the quantity x for which the revenue  is maximum. 5 4 3 1 Answer2
If y = 15 x2 ,  then d2 y / d2 x is —— 15 30 30 x 0 Answer2
If y =  e x + 10x2  ,  then d2y / d2x is —— ex 10 x 20 x ex + 20 Answer4
If the demand function is  D = 25 – 3p ,where D is demand and p is price, find the elasticity of demand at p = 5 0.50 1.50 2 2.50 Answer2
If the demand function is  D = 10 – 2p ,where D is demand and p is price, find the elasticity of demand at p = 2 2/3 1/3 1 1/4 Answer1
If the Revenue function is given by R = D2 – D + 10 . Find the marginal revenue  if the number of units demanded (D) = 1. 7 6 1 4 Answer3
If the Revenue function is given by R =  10 D2 + 10 D  – 2. Find the  marginal revenue  if the number of units demanded (D) = 20 400 10 410 450 Answer3
If the demand function is given by p = 20 + 10D. Find the average revenue   if the number of units demanded (D) = 4. 60 100 65 250 Answer1
If the cost function of manufacturing x items is given by 5x2 +10 x+ 20. Find the average cost if 2  items are made( x = 2) 60 30 20 40 Answer2
A function is given as f(x) = 10 x2 + 5x  – 10 , find its value at x = 1 -5 5 0 10 Answer2
A function is given as f(x) =  6x2 – 2x  + 15 , find its value at x = 2 30 5 35 10 Answer3
The simple interest  at 20% on Rs. 60,000  for 5
years is Rs.—-
60,000 1,20,000 50,000 65,000 Answer1
A bank promises to double the principal invested by their customers in 10 years. What
is the rate of simple interest offered by the
8% 10% 12% 14% Answer2
The   compound   interest   for   3   years   on   Rs. 15,000  at  the  rate  of  8%  per  year,  calculated annually is approx. Rs.—- 5,000 3,896 3,500 2,950 Answer2
The difference between the compound interest and the simple interest on a principal P, placed at 10% p.a. , compounded annually for 2 years is Rs. 50, then the principal P is Rs. —– 300000 400000 5000 600000 Answer3
A fixed sum kept on compound interest got Rs. 800  in  the  first  year  and  Rs.  864  in  the  next year.       Find   the   rate   of   interest    ,   when compounded annually. 9% 7% 8% 10% Answer3
A  sum  of  Rs. 25000  accumulated to  Rs. 55000 after 12 years. Find the rate of S.I. p.a. 30% 10% 40% 50% Answer2
The Compound interest  at 10 % on Rs. 40,000
for 2 years is Rs.—
8,000 9,500 8,400 12,000 Answer3
After   how   many   years,   a   sum   of   Rs.   6400 accumulated to  an amount of Rs. 9280 at  9% p.a. rate of simple Interest? 12 years 13 years 5 years 10 years Answer3
Ajay opened a recurring deposit account of Rs. 2,000 at the end of each year for 2 years. What is  the  accumulated  amount  if  the  interest  is compounded at 10% p.a.? Rs. 3,800 Rs.2,500 Rs. 4,200 Rs.3,545 Answer3
The    approximately    present    value    of    an immediate  annuity  of Rs. 500/-  per year  for  4 years with interest compounded at 11 % p.a. Rs.2,500 Rs.1,551 Rs.2,840 Rs.3,400 Answer2
Priya took some money from his friend at simple interest of 6 % per annum. She returned her friend Rs.1,180. After how much time did Priya return the money if she borrowed Rs. 1,000? 3 years 4years 2 years 6years Answer1
Manisha took a loan from a bank for 4 years at 12 % p.a. rate of simple interest. She paid Rs.1,440 as interest on a loan taken by her.
What was the amount she took as loan?
Rs.3,000 Rs.5,500 Rs.6,400 Rs.3,880 Answer1
Suresh  invested Rs. 500 in SBI for 2 years. He also invested Rs. 300 in ICICI for 4 years. At the end he received Rs. 220 in all from banks as total simple interest. What must have been rate of interest? 10% 11% 12% 9% Answer1
An amount of Rs.5,000 was borrowed by Anjali
, at a simple interest of 15 % p.a. . She returned the amount with interest after 4 years. Calculate the  total amount returned by her.
Rs.5,000 Rs.6,000 Rs.8,000 Rs.8,500 Answer3
The simple interest  at 14 % on Rs. 200 for 3 years is Rs—– 58 84 45 100 Answer2
The simple interest at 9 %, for a fixed deposit at the  end  of  6  years  was  Rs.  2,700,  then  the principal  of the fixed  deposit was Rs.—- 5,000 5,500 4,800 3,400 Answer1
At what rate a principal of Rs. 5,000 be put for 4  years,  so  as  to  get  Rs.2,400   as  interest on Maturity ? 6% 12% 10% 8% Answer2
When  the  interest  is  compounded  annually  , the   maturity   amounts   of   a   fixed   deposit obtained  at   the  end  of  one  year  using  the compound   interest   as   well    as   the   simple interest are identical. TRUE FALSE Partially true Depends on the principal Answer1
I  keep  Rs.  100  for simple interest in a  bank at 10%   for   2   years.   My friend keeps   Rs.   100 for compound interest at 10% for 2 years. If his interest is compounded annually,  what is the difference in our interests on maturity? Rs.100 Rs.1 Rs.10 Rs.1000 Answer2
A  person  borrowed  Rs  15,000  at  12%  interest
p.a.  If  he  is  supposed  to  return  the  money within 1 year, then his EMI using Flat  Rate of Interest will be  Rs.—
Rs.2,500 Rs.1,800 Rs.2,000 Rs.1,400 Answer4
Ruby borrowed Rs. 60,000 at  8 % interest p.a. If she is supposed to return the money within 2 years, then her  EMI using Flat Rate of Interest
will be  Rs.—
3,600 2,000 2,900 900 Answer3
The future value of Rs. 25,000 kept in a bank, after 1 year at a 15% rate of compound interest p.a. is Rs.—- 28,750 30,000 32,400 25,300 Answer1
The future value of Rs.45,000 kept in a fixed deposit account, after 2 years at  12 % rate of compound interest p.a. is Rs.—- 40,000 56,448 42,000 35,000 Answer2
The difference between the compound interest and the simple interest on a principal P, placed at 10% p.a. , compounded annually for 4 years is Rs. 1282, then the principal P is Rs. —- 20,000 10,000 15,000 25,000 Answer1
A sum of Rs. 12,000 accumulated to Rs. 17,280 at 20%p.a.compound interest. Find the period. 1year 3year 2year 4year Answer3
A sum of Rs.24,000 accumulated to Rs. 34,560 after a certain period , at  20 % p.a. rate of compound interest p.a.. Find the period 1 year 4 year 3 year 2 year Answer4
Find the approx present value of Rs.15,000 payable 3 years hence ,if the interest is compounded annually at 9 % p.a. Rs.15,700 Rs.16,450 Rs.11,583 Rs.16,000 Answer3
Preeti kept a certain amount in a fixed deposit in a bank which offered 10% rate of interest , compounded annually. At the time of maturity , after 4 years she received Rs. 73,205. Find the Principal amount Rs.50,000 Rs.80,000 Rs.75,000 Rs.85,000 Answer1
Ramesh deposited Rs. 8000 at the end of every year in a bank for 4 years. How much amount of annuties he received at the end if the rate of interest being 8 % p.a. Rs. 32,000 Rs.30000 Rs.25,000 Rs.36,050 Answer4
Radhika opened a recurring deposit in a bank for 6 years with payment of Rs. 5000. Find the total amount of annuties she will receive at the end of period with 9 % p.a. Rs.37,617 Rs.30,000 Rs.25,000 Rs.27,000 Answer1
Find the present value of an annuity of Rs. 2,000,paid at the end of each year for 4 years , at 11 %  compounded annually. Rs.8,000 Rs.6,205 Rs.8,200 Rs.9,000 Answer2
_is an interest earning fund , in which equal deposits are made at equal interval of time . Mutual fund Sinking Fund EMI Loan Answer2
Find the approx. present value of an annuity of Rs. 2,000 paid at the end of each year for 3 years , at 6 %  compounded annually Rs.8,760 Rs.5,346 Rs.6,700 Rs.7,500 Answer2
Amita deposited Rs. 5000 at the end of every year in a R. D. account  for 3 years. How much amount of annuties she received at the end if the rate of interest being 12 % p.a. Rs.10,300 Rs.14,000 Rs.12,200 Rs.16,872 Answer4
Puja took a loan of Rs.40,000  to be repaid in 2 year at  6 % p.a. . Find the approx.  EMI by Flat
interest rate method.
Rs.3,500 Rs.4,400 Rs.2,500 Rs.1,867 Answer4
Mansi  takes a loan of Rs. 2,40,000 from a bank for a period of 10 months. Compute  the EMI at 10 % p.a.by Flat interest rate method. Rs. 18,200 Rs.30,000 Rs.26,000 Rs.25,500 Answer3
Rajesh   takes a loan of Rs.10,000 from a financial institution for a period of  4 months. Compute  the EMI at 12 % p.a.by Flat interest
rate method.
Rs.2,600 Rs.5,000 Rs.3,500 Rs.7,200 Answer1
For EMI , rate of interest should be —- per annum per quarter per month per half year Answer3
The sum invested /borrowed is called the —— Interest accumulated
amount
EMI principal Answer4
A series of equal payments made at equal
interval of time is called the —–
Principal Amount Annuity Interest Answer3
If there exit a relation between a pair of
variables ( x and y) then it is called
correlation A.M. G.M. Median Answer1
A statistical data consisting of two variables is
called a
multivariate bivariate univariate polynomial Answer2
If both variables increase or decrease together
then there is           correlation
negative no positive perfect negative Answer3
The correlation coefficient lies between ± 1 ± 2 ± 3 0 & 1 Answer1
A pictorial representation of the correlation is
called
scatter diagram bar diagram histogram pie chart Answer1
For Perfectly positive correlation r = -1 -2 1 -3 Answer3
If the value of Pearson’s coefficient of correlation is – 0.93, it can be concluded that there is High degree of Positive correlation Perfect negative
correlation
No correlation High degree of negative correlation Answer4
For positive correlation if x  increases then y increases or if x decreases then —– y increases y decreases no change in y y increases and decreases both Answer2
If changes in x does not affect the changes in y then there is          correlation positive negative no perfect positive Answer3
The relationship between number of strikes of employees of a company and its production  is a example of ——
correlation
positive negative perfect positive no Answer2
The relationship between height and weight of a student is a example of          correlation negative perfect positive no positive Answer4
The relationship between I. Q. of a student and price of petrol  is a example of          correlation positive No negative Perfect positive Answer2
If the value of Pearson’s coefficient of
correlation is 1 , it can be concluded that there
is      correlation
Imperfect negative Perfect negative perfect positive imperfect positive Answer3
If the value of Pearson’s coefficient of
correlation is 0 , it can be concluded that there is —correlation
negative positive no perfect positive Answer3
The coefficient of rank correlation( R ) between marks given by judge A and judge B to a series of one act play in a drama competition is 0.75.
If  ∑ d2 = 30 then number of  the play group(n) is—-
9 11 12 13 Answer1
If n= 8 and ∑ d2  = 30  then  Spearman’s rank
coefficient of  correlation( R ) is……
0.85 1 0.64 2 Answer3
If n= 7 ,  ∑ d2   = 45 and ∑ c.f. = 1  then Spearman’s rank coefficient of  correlation( R ) is…… 0.4 0.18 0.5 0.8 Answer2
If n = 4 ,  ∑xy = 88 ,  ∑x = 16 ,  ∑y = 20,  ∑x2 = 80
and  ∑ y2  = 116 then Karl Pearson’s coeff. of
0.4 1 0.2 0.5 Answer4
If a rank is repeated twice then value of
correction factor (c.f.) is —–
1 2.00 0.5 1.5 Answer3
For the data x : 12 , 15 , 11 , 10   ;  y:  25,30,28,29 . The rank coeff. of correlation is —-
0.2 0.3 0.4 0.5 Answer1
If two variables of x & y are highly correlated then y can be estimated for a given value of x using regression equation of y on y y on x x on x x on y Answer2
x can be estimated for a given value of y using regression equation of                 If the two variables of x & y are highly correlated. x on x y on y x on y y on x Answer3
If the two regression coefficients are positive then the value of the correlation coefficient must be positive negative zero -1 Answer1
The correlation coefficient is always
If the two regression coefficients are negative.
1 0 positive negative Answer4
The Pearson’s correlation  is mean of both the regression coefficient. Arithmetic Geometric Harmonic cube Answer2
The regression equation is inter-relation between variables. 5 4 2 1 Answer3
If one of the regression coefficient is negative then the another regression coefficient is
.
negative positive 2 3 Answer1
If one of the regression coefficient is  > 1 then the another regression coefficient has to be > 1 < 1 1 -1 Answer2
If byx = 1.5 & bxy = 0.5 then r = 0.566 0.666 0.766 0.866 Answer4
If the two regression lines are perpendicular with each other, then the value of correlation coefficient is 5 4 0 3 Answer3
If the regression equation of x on y is x + 2y = 40, the estimated value of x when y = 10 is 5 10 15 20 Answer4
The estimated value of y when x = 9 is if the regression equation of y on x is 4x + 3y =
51.
5 4 3 2 Answer1
The value of the Correlation coefficient is      if the regression coefficients are 0.4 and 0.9 0.5 0.6 0.7 0.8 Answer2
The regression equations are given by x + 3y = 88   & 2x + y = 71 then mean values of x & y are                respectively. 20 & 22 23 & 26 25 & 21 24 & 27 Answer3
The regression equation of y on x is 100y-45x- 1400=0 & that of x on y is 4y-5x+200=0 then r = 0.6 0.7 0.8 0.9 Answer1
bxy = 1/3 and mean values of x & y are 15 & 20 respectively then regression equation of x on y
is
3x – y = 24 3x – y = 25 3x – y = 26 3x – y = 27 Answer2
byx = -4/5 and mean values of x & y are 20 & 25 respectively then regression equation of y on x is 4x + 5y = 202 4x + 5y = 203 4x + 5y = 204 4x + 5y = 205 Answer4
If r = 0.4 and standard deviation of x & y are 15
& 9 respectively then regression coefficient of y on x is
0.19 0.22 0.24 0.26 Answer3
The Regression coefficient of x on y is    If the standard deviation of x & y are 7 & 4 respectively  and r = – 0.8 -0.9 -1.4 -1.6 -1.9 Answer2
If r = 1/3 & bxy = 2/5 then byx = 5/16. 5/17. 5/18. 5/19. Answer3
An orderly set of data arranged in accordance with their time of occurrence is called series Arithmetic Geometric Harmonic Time Answer4
An increase in the number of patients in the hospital due to heatstroke is
variation
Regular Irregular Seasonal Non-Seasonal Answer3
In time series seasonal variations can occur within a period of   year Four Three One Nine Answer3
The general tendency of the time series data is represented using the following component Trend random constant variable Answer1
In a straight-line equation Y = a + bX; a is X-intercept Y-intercept Slope Variable Answer2
In a straight-line equation Y = a + bX; b is Slope Variable X-intercept Y-intercept Answer1
Moving average method is used for measurement of trend when it is variable constant non-linear linear Answer4
The most commonly used mathematical method for measuring the trend is by   method quarterly semi-annual least square Variable Answer3
Damages due to floods, earthquakes, strikes, fires and political disturbances are variation Regular Irregular Seasonal Cyclical Answer2
The Additive time series model can be
expressed as
O = T + S + C + I O = T x S x C x I O = T x S x C O = T x S Answer1
The multiplicative time series model can be expressed as O = T + S + C + I O = T x S x C x I O = T + S + C O = T + S Answer2
Index numbers are expressed in ratio Squares cubes Percentage Permutation Answer3
Index for base period is always taken as 100 200 300 400 Answer1
In chain base method, the base period is Four Three Two Not Fixed Answer4
Price relatives are a percentage ratio of current year price and Base year quantity Previous year
quantity
Base year
price
Current year
quantity
Answer3
Another name of consumer’s price index number is Wholesale index Cost of living
index
Sensitive
index
Composite index Answer2
Cost of living index numbers are obtained by formula Laspeyre’s Paasche’s Fisher Marshall
Edgeworth
Answer1
When the current price is divided by the price of the preceding year, we get        relative non-link Compound Complex link Answer4
The method of link relatives is used to calculate index Paasche’s Fisher Chain Base Laspeyre’s Answer3
A number that measures a relative change in a single variable with respect to a base is Number Good Index Great Index Simple Index Quantity Index Answer3
The Trend value data for 3 consecutive years is 58, 62 & 78  then 3 yearly moving average is 55 66 77 88 Answer2
The Trend value data for 5 consecutive years is 73, 82, 95, 102 & 103  then 5 yearly moving average is 89 90 91 92 Answer3
To obtain 5 yearly moving average for a year the corresponding 5 yearly moving total is to be divided by 5 4 3 2 Answer1
The 4 yearly moving average for a year whose corresponding 4 yearly centered total is 496 has to be 60 61 62 63 Answer3
The 3 yearly moving average for a year whose corresponding 3 yearly moving total is 546 has to be 182 183 184 185 Answer1
The 5 yearly moving average for a year whose corresponding 5 yearly moving total is 265 has to be 50 51 52 53 Answer4
If a = 5 & b = 7 then the Trend line equation is given by y = 7 + 5x y = 5 + 7x x = 5 + 7y x = 7 + 5y Answer2
If n = 7 then to find trend line equation y = a + bx by least square method x takes the values as ,-3,-2,-1,0,1,2,3, ,1,2,3,4,5,6,7, ,1,3,5,7,9,11,1
3,
,2,4,6,8,10,12,14, Answer1
If n = 6 then to find trend line equation y = a + bx by least square method x takes the values as ,1,2,3,4,5,6, ,-5,-3,-1,1,3,5, ,1,3,5,7,9,11, ,2,4,6,8,10,12, Answer2
If ∑y = 240 & n = 12 then in trend line equation y = a + bx we have a = 17 18 19 20 Answer4
If ∑P0 = 80 & ∑P1= 100 then simple index number by aggregative method is 115 120 125 130 Answer3
If ∑i = 480 & n = 6 then simple index number by average of price relative method is 50 60 70 80 Answer4
If ∑P0w = 303 & ∑P1w = 500 then index number by weighted aggregative method is 145.02 155.02 165.02 175.02 Answer3
If ∑iw = 4200 &  ∑w = 20 then cost of living index number by family budget method is 200 210 220 230 Answer2
If ∑p1q0 = 400 & ∑p0q0 = 210 then Laspeyre’s Index number = 190.48 192.48 194.48 196.48 Answer1
If ∑p1q1 = 1610 & ∑p0q1 = 1090 then Paasche’s Index number = 137.71 147.71 157.71 167.71 Answer2
If Laspeyre’s  & Paasche’s Index number are 80 & 90 respectively then Fisher’s Index number is 64.85 74.85 84.85 94.85 Answer3
If Laspeyre’s  & Paasche’s Index number are 64 & 72 respectively then Dorbish-Bowley’s Index number is 62 64 66 68 Answer4
If ∑p1q0 = 400, ∑p0q0 = 210, ∑p1q1 = 490 & ∑p0q1 = 300 then Marshal Edgeworth’s Index number = 164.51 174.51 184.51 194.51 Answer2
Dorbish-Bowley’s Index number is           of Laspeyre’s  & Paasche’s Index number Harmonic Mean Geometric Mean Difference Arithmetic mean Answer4
The mean of the binomial distribution is given
by
n np npq p+q Answer2
The variance of the binomial distribution is given by p+q n np npq Answer4
The variance of binomial distribution is always mean. thrice to more than less than twice the Answer3
Each trial in the binomial distribution has
possible outcomes.
1 2 3 4 Answer2
In binomial distribution we always have p + q = 1 3 5 7 Answer1
The mean of Poisson’s distribution is always variance. more than less than twice the equal to Answer4
The Poisson distribution has a parameter. 3 2 1 0 Answer3
The mean of the Poisson’s distribution is given by m n pq p+q Answer1
The variance of the Poisson’s distribution is given by pq m p+q n Answer2
We use Poisson’s distribution when ‘n’ is large & probability of success (p) is large not known fixed small Answer4
In  Normal distribution, Total area under the normal curve is 4 3 2 1 Answer4
We use normal distribution when x is small continous not known fixed Answer2
In  Normal distribution, Shape of normal curve can be related to square rectangle triangle bell Answer4
In case of symmetrical normal distribution we
always have
mean = mode =
median
mean < mode mean > mode mean < median Answer1
The normal distribution has parameters. 0 1 2 3 Answer3
In  Normal distribution, the shape of normal curve depends upon  deviation Geometric Standard Quartile Quadratic Answer2
In  Normal distribution, the normal curve is symmetrical about y = 2x x = 2y y = mean x = mean Answer4
In  Normal distribution, area under the normal curve on either side of ordinate is 0.5 0.6 0.7 0.8 Answer1
In  Normal distribution, the Quartile deviation is  standard deviation more than less than equal to thrice the Answer2
In  Normal distribution, the Standard deviation is Mean deviation less than equal to more than twice the Answer3
In a binomial distribution, If mean = 4 and n = 5 then p = 0.8 0.7 0.6 0.3 Answer1
In a binomial distribution, If n = 8 and mean = 2.4 then q = 0.2 0.4 0.6 0.7 Answer4
In a binomial distribution, If mean = 3 and p = 0.5 then n = 8 7 6 5 Answer3
In a binomial distribution, If n = 6 and q = 0.7 then mean = 1 1.8 2 3 Answer2
In a binomial distribution, If p = 0.4 and n = 7 then variance = 3 2 1.68 1 Answer3
In a binomial distribution, If  variance = 0.8 and q = 0.8 then n = 1 2 3 5 Answer4
In a binomial distribution, If  mean = 3 and variance = 2.4 then p = 0.2 0.3 0.4 0.5 Answer1
In a binomial distribution, If variance = 2 and mean = 3 then n = 8 9 10 12 Answer2
In a binomial distribution, If n = 5 and p = 0.6 then mode = 2 4 3 6 Answer3
In a binomial distribution, If n = 4 and q = 2/3 then P(X=4) = 1/21. 1/31. 1/41. 1/81. Answer4
In a Poisson’s distribution, If n = 300 and p = 1% then mean = 0 3 6 9 Answer2
In a Poisson’s distribution, If variance = 2 and p = 4% then n = 50 60 70 80 Answer1
In a Poisson’s distribution, If mean = 3.8  then mode = 0 2 3 5 Answer3
In a Poisson’s distribution, If mean = 4  then standard deviation = 1 2 3 5 Answer2
In a Poisson’s distribution, If P(X=1) = P(X=2) then m = 7 5 3 2 Answer4
In a Poisson’s distribution, If standard deviation= 3 and n = 300 then p =            % 0 2 3 4 Answer3
In a Poisson’s distribution, If P(X<1) = 0.83 then P(atleast one) = 0.17 0.18 0.19 0.21 Answer1
In a Poisson’s distribution, If P(X = 0) = 0.14, P(X= 1) = 0.17 & P(X = 2) = 0.23 then P(X < 3) = 0.24 0.32 0.41 0.54 Answer4
In a Normal distribution, If P(0 < z < 2) = 0.4772 then P(-2 < z < 2) = 0.6255 0.9544 0.7255 0.8255 Answer2
In a Normal distribution, If P(0 < z < 1) = 0.3413 then P(z > 1) = 0.1355 0.1455 0.1587 0.1655 Answer3

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